16t^2-33t+6=22

Solution for 16t^2-33t+6=22 equation:

16t^2-33t+6=22

We move all terms to the left:

16t^2-33t+6-(22)=0

We add all the numbers together, and all the variables

16t^2-33t-16=0

a = 16; b = -33; c = -16;
Δ = b2-4ac
Δ = -332-4·16·(-16)
Δ = 2113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-\sqrt{2113}}{2*16}=\frac{33-\sqrt{2113}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+\sqrt{2113}}{2*16}=\frac{33+\sqrt{2113}}{32}
$